Corways Game solution

[Anup Atluri]

Code:

#include <iostream>
#include <stdlib.h>
#include <stdio.h>
#include <conio.h>
#include<windows.h>
using namespace std;

void display(int a[11][11]);
void check(int a[11][11],int i,int j);
void delay();
int count(int a[11][11],int i,int j);
/*gotoxy was removed from <conio.h>
  Hence, the function is defined using
  other inbuilt functions from <windows.h>*/

void gotoxy (int x, int y)
   {
       COORD coord;
       coord.X = x; coord.Y = y;
       SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), coord);
   }

int main()
{
    int a[11][11]={};
    /*create an array with all cells in the boundary
      having 2 as their value(they will not be displayed).
      Thus, we can generalise the condition checking for all cells.*/
    for(int i=0,j=0;j<11;j++)
    {
        a[i][j]=2;
        a[j][i]=2;
    }
    for(int i=10,j=10;i>0;i--)
    {
        a[i][j]=2;
        a[j][i]=2;
    }


    int n;
    /*enter ur initial conditions here or
      include a block which allows u to do so*/
    a[6][3]=1;
    a[6][4]=1;
    a[6][5]=1;
    a[5][3]=1;
    a[5][4]=1;
    a[5][5]=1;
    a[3][3]=1;
    a[3][4]=1;
    a[3][5]=1;
    display(a);
    cout<<"Enter the number of times to be run: ";
    cin>>n;
    for(int k=1;k<=n;k++)
    {

        for(int i=1;i<10;i++)
        {
            for(int j=1;j<10;j++)
            {
                check(a,i,j);
            }
          delay();
          display(a);
          cout<<"\n\n";
        }

    }



    cout<<"\n\n\n";
    return 0;
}
void check(int a[11][11],int i,int j)
{

                if(a[i][j]==1)
                {
                    int c=count(a,i,j);
                    if(c<2 || c>3)
                    {
                        a[i][j]=0;
                    }

                }

                if(a[i][j]==0)
                {
                    int c=count(a,i,j);

                    if(c==3)
                    {
                        a[i][j]=1;
                    }
                }


      return;
}
void display(int a[11][11])
{
    for(int i=1;i<10;i++)
    {
        for(int j=1;j<10;j++)
        {
          gotoxy(j,i);
          cout<<a[i][j];
        }
       
    }
    cout<<endl;
}


void delay()
{
    for(int i=0;i<100;i++)
    for(int j=0;j<100;j++)
    for(int k=0;k<1000;k++);

}

int count(int a[11][11],int i,int j)
{
    int count=0;
    for(int k=i-1;k<=i+1;k++)
    {
        for(int l=j-1;l<=j+1;l++)
        {
            if((i!=k||j!=l)&&a[k][l]==1)
            {
                count++;
            }
        }
    }
    return count;
}


[nagashayan]

#include<windows.h>
its windows programming can you tell me where can i execute a simple windows programing code.. as i tried in visual c++ iam getting some errors like include stdfix.h....

[Anup Atluri]

#include<windows.h>
its windows programming can you tell me where can i execute a simple windows programing code.. as i tried in visual c++ iam getting some errors like include stdfix.h....

u can use codeblocks for windows !!! that's where the above program was run !!

[tejassrinivasan]

anup, from next time can u please post the details of the question, i had to google it to know wat it is

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